# Line slope calculator x-4y=3

**Straight line given by points A[3; 0] and B[7; 1]**

## Calculation:

**Slope-intercept form of line:**y = 0.25x-0.75

**Canonical form of the line equation:**x-4y-3 = 0

**Parametric form of the line equation:**

x = 4t+3

y = t ; t ∈ R

**Slope:**m = 0.25

**Slope angle of line: φ =**14°2'10″ = 0.245 rad

**X intercept:**x

_{0}= 3

**Y intercept:**y

_{0}= q = -0.75

**Distance line from the origin:**d

_{0}= 0.7276

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; 1)

**Normal vector: n =**(1; -4)

**Midpoint of the segment AB: M =**[5; 0.5]

**Perpendicular Bisector equation:**4x+y-20.5 = 0

**Vector OA = (3; 0) ; |OA| = 3**

**Vector OB = (7; 1) ; |OB| = 7.0711**

**Scalar product OA .OB = 21**

**Angle ∠ AOB = 8°7'48″ = 0.1419 rad**